Find the equation of the line in slope intercept form parallel to 5x−5y=−2 and goes through the point (−10,4) y=?

y = x + 14

Step-by-step explanation:

given

5x−5y=−2, we'll rearrange this into slope - intercept form

5x + 2 = 5y

5y = 5x + 2    (divide both sides by 5)

y = x + (2/5)

recall that the general equation of the slope-intercept form of a linear equation:

y = mx + b, the value of m represents the slope of the line

in our case, comparing the above equations, it is clear that the slope m = 1.

We are given that our line is parallel to the above line, hence it will also have  a slope of 1.

if we substitute m = 1 into the general equation, we will get

y = x + b

in order to find the value of b, we will substitute the given point (-10,4) into the equation:

4 = -10 + b   (add 10 to both sides)

b = 4 + 10

b = 14

hence our equation is y = x + 14

step-by-step explanation:

this is not possible to solve with the info given.   you need at least an one angle somewhere.

complete the steps to find the area of the trapezoid.

area of rectangle = 256   square units

area of triangle 1 = 24  square units

area of triangle 2 = 16  square units

area of triangle 3 =   96 square units

area of trapezoid = 120  square units

step-by-step explanation: