A bank representative studies compound interest, so she can better serve customers. She analyses what happens when $2,000 earns interest several different ways at a rate of 2% for 3 years. a. Find the interest if it is computed using simple interest
b. Find the interest if it is compounded annually.
c Find the interest if it is compounded semi-annually.
d. Find the interest if it is compounded quarterly e. Find the interest if it is compounded monthly.
f. Find the interest if it is compounded daily
g. Find the interest if it is compounded hourly. h. Find the interest if it is compounded every minute.
i. Find the interest if it is compounded continuously.
j. What is the difference in total interest if computed using simple interest or if compounded continuously?

Given that a bank representative studies compound interest, so she can better serve customers. She analyzes what happens when $2,000 earns interest several different ways at a rate of 2% for 3 years.a) the interest if it is computed using simple interest. 12.00= dollarsb) the interest if it is compounded annually.= dollarsc) the interest if it is compounded semiannually=d) the interest if it is compounded quarterly.=e) the interest if it is compounded monthly.=

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841