Prove that P(2,3), (3, 4), R(5, 6) and S(4,5) are the
vertices of a rhombus

Solution :-

Given coordinates to us are ,

Here it is asked to Prove that these are vertices of Rhombus . So we know that all sides of a Rhombus are equal .So if we show that value of all sides lenght are equal , then it will be a Rhombus .

We will use Distance Formula .

Now , here ,

Distance between P and Q :

⇒ x = √ (2 - 3)² + (3-4)² .

⇒ x = √ (-1)² + (-1)² .

⇒ x = √ 1 + 1 .

⇒ x = √2 .

Distance between Q and S :

⇒ x =√ [ (3-4)² + (5-4)².

⇒x = √ 1² + 1² .

⇒ x = √ 1 + 1 .

⇒ x = √2 .

Similarly we can prove other distances equal.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

nada

step-by-step explanation: