Which of the following is the solution to 3 | x -1 | >= 12 O A. X <= -3 or x >= 5
O B. X>= -3 or x>= 5
OC. X<= -3 and x>= 5
O D. x>=5

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step-by-step explanation:

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< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐