If we have a group of 5 men and 4 women and we select two at random, without replacement, then find the probability that one of each gender is selected

Step-by-step explanation:

If we have a group of 5 men and 4 women, the total number of people we have is 5+4 = 9 people

Total outcome = 9people

For us to select one of each gender without replacement and selecting two at random means we can select a male before a female or a female before a male.

Let W =Women and M = Male

The Probability of selecting two at random without repalcement is given as;

= Pr(W)Pr(M) + Pr(M)Pr(W)

= (4/9*5/8)+(5/9*4/8) (Note that the total number reduces by 1 during the second pick since we aren't replacing the person we picked first)

= 20/72 + 20/72

= 40/72

= 20/36

= 5/9

Hence the the probability that one of each gender is selected is 5/9

21

step-by-step explanation:

i honestly dont know