Use the given conditions to write an equation for the line in point-slope form and in slope-intercept form. Passing through -3, -6) and parallel to the line whose equation is y=-4x+1

Step-by-step explanation:

Hey there!

The equation of a st.line passing through point is;

(y + 6) = m1(x+3).........(i). [ Use one point formula]

y = -4x + 1............(ii)

Comparing 2nd equation with y = mx+c, we get;

Slope (m2) = -4.

For parallel lines;

(i.e m1=m2 = -4)

Putting value of slope in 1st equation,

Smplify them to get equation.

Therefore the required equation is y = -4x-18.

Hope it helps..

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

answer: 1 and 3

step-by-step explanation: