20 years ago the age of father was 5 times the age of his son. at peesent father's age is 10 years more than twice his sons. find theur present ages URGENT FAST HELP PLEASE

Step-by-step explanation:

At present:

Let son's age = x

Father's age = 2x + 10

Before 20 years:

son's age = x - 20

Father's age = 2x + 10 - 20 = 2x - 10

Father's age = 5 * (Son's age)

         2x - 10 = 5*(x - 20)

        2x - 10 = 5x - 100 {add 100 to both sides}

2x -10 + 100 = 5x - 100 +100

     2x  + 90 = 5x            {Subtract  2x from both sides}

2x + 90 - 2x = 5x- 2x

             90  = 3x               {divide both sides by 3}

          90/3 = x

x = 30

Present age of :

Son = 30 years

Father = 2*30 +10 = 60 + 10

           = 70 years

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

37

step-by-step explanation: