Find the uncertainty in a calculated average speed from the measurements of distance and time. Average speed depends on distance and time according to this function v(t, x) = x/t. Your measured distance and time have the following values and uncertainties x = 6.1 meters, 2.3 meters and t = 6.3 seconds and 1.5 seconds. What is the uncertainty in the average speed, ? Units are not needed in your answer.

The uncertainty in the average speed is 0.134 meters per second.

Step-by-step explanation:

Let be the average speed function, we calculate the uncertainty in the average speed by total differentials, which is in this case:

Where:

- Uncertainty in the average speed, measured in meters per second.

- Partial derivative of the average speed function with respect to distance, measured in .

- Partial derivative of the average speed function with respect to time, measured in meters per square second.

- Uncertainty in distance, measured in meters.

- Uncertainty in time, measured in seconds.

Partial derivatives are, respectively:

,

Then, the total differential expression is expanded as:

If we get that , , and , the uncertainty in  the average speed is:

The uncertainty in the average speed is 0.134 meters per second.

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)