(h+k)(2)=?
(h-k)(3)=?
3h(2)+2k(3)=?

see explanation

Step-by-step explanation:

(h + k)(x) = h(x) + k(x), thus

h(x) + k(x)

= x² + 1 + x - 2 = x² + x - 1 , then

(h + k)(2) = 2² + 2 - 1 = 4 + 2 - 1 = 5

(h - k)(x) = h(x) - k(x), thus

h(x) - k(x)

= x² + 1 - (x - 2) = x² + 1 - x + 2 = x² - x + 3, then

(h - k)(3) = 3² - 3 + 3 = 9 - 3 + 3 = 9

h(2) = 2² + 1 = 4 + 1 = 5

k(3) = 3 - 2 = 1

Thus

3h(2) + 2k(3)

= 3(5) + 2(1) = 15 + 2 = 17

if you was gonna solve for a, a is a   < -12