Given the coordinates of the Triangle SKY with vertices S(-6, -5), K(-1, -2), Y(-4, -7) and along with the given scale factor and center of dilation: Scale factor = 1/2, centered at the origin. What is the coordinate of the image for K' (___, ___)

Your

(-4, -2)

( -2, -4)

( -1/2, -1)

( -1, -1/2)

x = 12

y = 15

step-by-step explanation:

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

idk

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.