The sum of three consecutive integers is 528. find the largest of these integers.
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[(n) +( n + 1) + (n + 2)]  = 528..  3n + 3 = 528.. 3n = 525...  n = 125.   Because it is three consecutive integers, your three numbers are 125, 126, 127.  Your answer is 127(Largest integer)

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)