X + 3y + 2z = 7 2x- y+z=9
-z+ 4y + 5z = 14

The answers are 2,-1,4 but I need help with showing the work plz!!!

Step-by-step explanation:

x + 3y + 2z = 7

2x − y + z = 9

-x + 4y + 5z = 14

First add the first and third equations to eliminate x.

7y + 7z = 21

Simplify:

y + z = 3

Solve for y:

y = 3 − z

Substitute into the first two equations:

x + 3(3 − z) + 2z = 7

2x − (3 − z) + z = 9

Simplify:

x + 9 − 3z + 2z = 7 → x − z = -2

2x − 3 + z + z = 9 → 2x + 2z = 12 → x + z = 6

Add the equations to eliminate z.

2x = 4

x = 2

Therefore, z = 4 and y = -1.

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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(c, 0) i might be wrong so don't put full faith on my answer