The solution for 7(5x+9)=12-(x+9) and simplified

x= -5/3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

7(5x+9)=12−(x+9)

7(5x+9)=12+−1(x+9)(Distribute the Negative Sign)

7(5x+9)=12+−1x+(−1)(9)

7(5x+9)=12+−x+−9

(7)(5x)+(7)(9)=12+−x+−9(Distribute)

35x+63=12+−x+−9

35x+63=(−x)+(12+−9)(Combine Like Terms)

35x+63=−x+3

35x+63=−x+3

Step 2: Add x to both sides.

35x+63+x=−x+3+x

36x+63=3

Step 3: Subtract 63 from both sides.

36x+63−63=3−63

36x=−60

Step 4: Divide both sides by 36.

36x/36 and -60/36

x= -5/3

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval

a) 40 more; b) old factory:   10%, new factory:   16%; c) week 4

explanation:

a) at week 0, we see in the graph that the new factory produces 190 specialty items.  

using the function, substituting 0 in for w,

this is a difference of 230-190 = 40.

b) the function for the old factory is written in the form f(x) = a(1+r)ˣ, where a is the original amount, x is the amount of time and r is the growth rate.   the equation for the old factory is ; 230 is in place of a and is the original amount; w is the amount of time; which means 1+r = 1.1.   this means that r must be 0.1 or 10%.

for the new factory, we find the percent of increase to find the growth rate; the formula for this is

between the first two points, the amount of change is 220-190 = 30; this gives us

30/190 = 0.158 ≈ 0.16 = 16%

c) at week 0, the old factory has 230 while the new factory has 190.

at week 1, the old factory has 230(1.1) = 253 while the new factory has 220.

at week 2, the old factory has 230(1.1²) = 278.3 while the new factory has 252.

at week 3, the old factory has 230(1.1³) = 306.13 while the new factory has 290.

at week 4, the old factory has 230(1.1⁴) = 336.743 while the new factory has 337.   this is the first week that the new factory surpasses the old.