A new community sports complex built in Oak Valley. The perimeter of the rectangular playing field is 434 yards. The length of the field is 8 yards less than quadruple the width. What are the dimensions of the playing field?

231 yards

Step-by-step explanation:

Let w = the width

Let 4w - 9 = the length

P = 2l + 2w

582 = 2(4w - 9) + 2w

582 = 8w - 18 + 2w

582 = 10w - 18

600 = 10w

60 yards = w

4w - 9 = 4(60) - 9 = 231 yards

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

she drove 134 miles

step-by-step explanation: