The larger of two numbers is three less than three times the smaller number. If the sum of the numbers is 61, what are the two numbers?

The numbers are 45 and 16.

Step-by-step explanation:

Let, the larger number be A and the smaller one be B.

By question we have,

or, A + 3 = 3B

Arrange,

or, A - 3B= - 3(I)

next, A + B=61(I I)

solving, from equation (I)

or, A - 3B = - 3

or, A=3B - 3

now putting this value of A in eqn (I I)

or, A+B=61

or, 3B - 3 +B = 61

or, 4B = 61+3

or, 4B = 64

or, B= 64/4

so, B = 16

now substituting value of B in the eqn just another from which we get B right now.

or, A= 3B - 3

or, A= (3×16) -3

or, A= 48 - 3

so, A= 45

Therefore, the numbers are 45 and 16.

Hope it Helped.

answer: the resulting cross section is a rectangle. solution: a plane parallel to the base of a triangular prism will intersect a cross section that is the same shape as its bases. so the cross section is a triangle.

step-by-step explanation: