What else would need to be congruent to show that ABC XYZ by ASA?

Explanation:

ASA stands for "angle side angle".

To use ASA, we must have two pairs of congruent angles, as well as a pair of congruent sides. The sides must be between the angles in question.

So far we're given

The thing we're missing is the other pair of congruent angles. So the missing congruent pair of angles is Angle Y = Angle B as those two angles are adjacent to the segments mentioned above.

Something like angle A is not adjacent or touching segment CB. Also, angle X is not adjacent to segment ZY. So we can rule these angles out. We'd only use these angles if we were dealing with AAS instead of ASA.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.