Mathematics, 06.10.2020 22:01 Usman458
cos b= 1/2[sin(a+b)+sin(a-b)]. A. cos a B. sin a C. cos b D. sin b
Answers: 2
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cos b= 1/2[sin(a+b)+sin(a-b)]. A. cos a B. sin a C. cos b D. sin b...
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