If the sum of 4 consecutive numbers is 126, what is the first number?
The first number is

Work Shown:

Consecutive numbers follow right after another (eg: 7,8,9,10,...)

x = first number

x+1 = second number

x+2 = third number

x+3 = fourth number

Add up the expressions and set this equal to 126

(x) + (x+1) + (x+2) + (x+3) = 126

x+x+1+x+2+x+3 = 126

(x+x+x+x) + (1+2+3) = 126

4x+6 = 126

4x = 126-6

4x = 120

x = 120/4

x = 30 = first number

x+1 = 30+1 = 31 = second number

x+2 = 30+2 = 32 = third number

x+3 = 30+3 = 33 = fourth number

Check:

30+31+32+33 = 126

Answer is confirmed.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.