Find four consecutive integers such that the sum of the second and fourth is 132.

let's consider the 4 consecutive numbers first.

x , x+1 , x+2, x+3

Now, according to the question,

2nd and 4th number should be 132.

Thus,

(x+1) +(x+3) = 132

2x + 4 = 132

2x = 128

x = 64.

So the 4 numbers are: 64...65...66..67

now if u add 65 and 67.. u will get 132

cheers :)

the answer is 28

step-by-step explanation:

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d