Let x represent the dollar amount spent on supermarket impulse buying in a 10-minute (unplanned) shopping interval. Based on a newspaper article, the mean of the x distribution is about $34 and the estimated standard deviation is about $7. A button hyperlink to the SALT program that reads: Use SALT. (a) Consider a random sample of n = 80 customers, each of whom has 10 minutes of unplanned shopping time in a supermarket. From the central limit theorem, what can you say about the probability distribution of x, the average amount spent by these customers due to impulse buying

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Step-by-step explanation:

Given the following :

Population mean (Mp) = 34

Population standard deviation (sd) = $7

Number of customers (n) = 80 customers

According to the central limit theorem:

If the number of samples is large (usually ≥ 30), then the distribution will be normal and mean of sample will be the same as the mean of population.

Population mean(Mp) = sample mean(Ms)

Mp= Ms

$34 = $34

Sample standard deviation = standard error

Standard Error(SE) = (population standard deviation / √n)

SE = 7 / √80

SE = 7 / 8.9442719

SE = 0.7826237 = $0.78

Hence, sample distribution is Normally distributed with a mean of $34 and standard deviation of $0.78

what is the information provided?

step-by-step explanation:

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b