An observation deck extends 201 feet out above a valley. The deck sits 151 feet above the valley floor. If an object is dropped from the observation deck, its height h in feet, after t seconds, is given by h=-16t^2+151 . How long will it take for the object to be feet above the valley floor?

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An observation deck extends 201 feet out above a valley. The deck sits 151 feet above the valley floor. If an object is dropped from the observation deck, its height h in feet, after t seconds, is given by h=-16t^2+151 . How long will it take for the object to be 6 feet above the valley floor?

Given the height of an object dropped from the observation deck modeled by the equation h(t) = -16t²+151. In order to know how long it will take for the object to be feet above the valley floor, we will substitute the height of the valley value into the equation;

h(t) = -16t²+151

If h = 6 feet

6 =  -16t²+151.

6-151 = -16t²

-145 = -16t²

t² = -145/-16

t² = 145/16

t² = 9.0625

t = √9.0625

t = 3.01seconds

Hence it will take 3.01secs take for the object to be 6 feet above the valley floor.

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answer: 298143

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