The prices of some jewelry sets in a store are shown below:

store price
a $110,000
b $100,000
c $1,110,000
d $130,000
e $120,000

based on the data, should the mean or the median be used to make an inference about the price of the jewelry sets in the store?
mean, because it is in the center of the data
median, because it is in the center of the data
median, because there is an outlier that affects the mean
mean, because there are no outliers that affect the mean

(C) Median, because there is an outlier that affects the mean

Step-by-step explanation:

The given data set is:

A$110,000

B$100,000

C$1,110,000

D$130,000

E$120,000

Since, in the given data set, there is an outlier that is $1,110,000 is present and we know that in order to make any inference about the data set, if an outlier is present in the given data set, then we cannot use mean to make any inference, hence median can be used in its place.

Thus, option C is correct that is Median, because there is an outlier that affects the mean.

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.