$80,000, and if it is installed, no losses from this type of incident will be incurred. However, if the generator is not installed, there is a 12% chance that a power outage will occur during a year. If there is an outage, there is a .07 probability that the resulting losses will be very large, or approximately $7 million in net aggregated loss. Alternatively, it is estimated that there is a .93 probability of only slight losses of around $1 million. Using decision tree analysis, determine whether the SPEA should have install the new power generator. What considerations may change your decision?

SPEA should have install the new power generator.

Step-by-step explanation:

The information provided is as follows:

Consider the decision tree attached below.

The loss that will be incurred after the generator is installed is, $80,000.

Compute the loss that will be incurred if the generator is not installed as follows:

The loss that will be incurred if the generator is not installed is $170,400.

The loss from not installing the generator is more than from installing it.

Thus, SPEA should have install the new power generator.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

-232

step-by-step explanation: