The length is 5 units less than 2 times the width. the perimeter is 22 units more than twice the width. find the length and width

L=length
W=width
P=perimeter
Start by creating equations based on what you know from the question
We know...
L=2w-5 (length is five units less then 2 times the width)
P=2w+22 (perimeter is 22 units more than twice the width)
P=2L+2w (perimeter formula)
Sub in everything we know into the perimeter formula (the P and L) and solve for w.
2w+22=2(2w-5)+2w
2w+22=4w-10+2w
22+10=4w+2w-2w
32=4w
W=8
Then sub w into the length formula to find L.
L=2w-5
L=2(8)-5
L=16-5
L=11
I hope this helps!