A peach farmer has two different varieties (named Variety A and Variety B) of peach trees on her land. Thirty percent of her trees are Variety A peaches and the other 70% are Variety B peaches. The weights of Variety A peaches are normally distributed with a mean of 90 grams and a standard deviation of 8 grams. The weights of Variety B peaches are normally distributed with a mean of 107 grams and a standard deviation of 12 grams. a. What proportion of Variety A peaches weigh between 100 and 110 grams

12.03%

Step-by-step explanation:

The z score i used to measure by how many standard deviations the raw score is above or below the mean. It is given by the equation:

a) For variety A, the mean = μ = 90, standard deviation = σ = 8

For x = 100 grams:

For x = 110 grams:

From the normal distribution table, P(100 < X < 110) = P(1.11 < z < 2.22) = P(z < 2.22) - P(z < 1.11) = 0.9868 - 0.8665 = 0.1203 = 12.03%

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation:

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step-by-step explanation: