A ball is thrown straight up from a height of 3 ft with a speed of 32ft/s. It’s height above the ground after x seconds is given by the quadratic function y=-16x^2+32x+3 Explain the steps you would use to determine the path of the ball in terms of a transformation of the graph of y=X^2.

My first steps is to enter the equation into desmos and see what the coordinates are which is (1, 19) 1 to the left and 19 up. The function is narrow and goes below the x axis.

Step-by-step explanation: Got it right (btw you can copy my answer and put it on edge) that way our answers aren't all the same :) bye!!

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