A picture is x+20 cm in width and 2x-10 cm in length. The frame is a constant 5 cm wide from the edge of the picture to the outside of the
frame. What is the area of just the frame?

A = 1100cm^2

Step by step Explanation:

given the dimensions of width and length of the picture are x+20 by 2x-10 and the frame is a constant 5 cm wider from the edge of the picture to the frame, than the area of the frame is defined as (x+30)(2x)-(x+20)(2x-10) = 30x+200.

If the width is equal to the length which I assume is true if the width is constant.

than x+30=2x, which means x = 30.

if this is true than 30(30)+200 = 1100cm^2

y= 2x+7

changed to y= 5x +7

as slope is increased from 2 to 5

therefore it would be less steeper

so, option d) is correct

4+3x is the answer

hope you got it