Problem 2: The perimeter of a rectangle is 72 meters. The width of the rectangle is 4 meters less than its length.
Part A: Which equation could be used to find the width and length of the
rectangle?
A. 1 + ((-4) = 72
C. (+2(e- 4) = 72
B. 21+ 2(1 - 4) = 72
D. 21 + ((-4) = 72

i think its a and d

step-by-step explanation:

40 x 50 = 2000

step-by-step explanation:

let x and 400 - x be the two numbers.  

==> 0.80x + 0.85(400 - x) = 400 - 68 from the statement of the problem.  

< ==> 0.80x + 0.85(400 - x) = 400 - 68  

==> 340 - 0.05x = 332  

< ==> -0.05x = -8 ==> x = 160, the first number ==> 400 - x = 240, the second number.