What is the most precise name for quadrilateral ABCD with vertices A(-5,2), B(-3,4), C(5,4), and D(3,2)?

Step-by-step explanation:

Parallelogram.

To get from A to B you move 2 units left and 2 units up

To get from B to C you move 8 units right and no units up or down.

To get from C to D you move 2 units down and 2 units left.

To get from D to A you move 8 units left and no units down or up.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this