The following sketch shows how to make an open-top box from a flat sheet of cardboard with cuts (heavy lines) and folds (dashed lines) as indicated. The dimensions of the resulting box depend on the length x of the corner cuts. 12 40 20 a. Show ow the volume of the box depends on length x of the corner cuts.

i. Excess each dimension of the box-length, width, and height-as a furation of x.

ii. Us: the formula for volume V of a box to write V as a function of x.

iii. Write the volume expression in expanded standard polynomial form.

b. Analyze the volume function for the box by answering the following questions.

i. Sketch a graph of y = V(x) for values of x that make sense in this situation.

ii. Estimate coordinates of the x-intercepts and local maximum and minimum points on the graph of V(x).

iii. Explain what the x-intercepts and local maximum and minimum points tell about the way the volume of such a box depends on the length x of the cuts.

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

0.0076, if you meant 4.125 divided by 0.03125 it would be 132

step-by-step explanation:

first you have to move the decimal in 0.03125 over until its behind the 5 which is 5 places over. now the number is 3125

then you have to move the decimal in 4.125, 5 places over. now the number is 4,112,500.

now you divide like you would normally would and get 0.0076

given : the shape of his satellite can be modeled by   where x and y are modeled in inches.

now,the given equation   is a equation of parabola.

here, coefficient of x is positive, hence the parabola opens rightwards.

on comparing this equation with standard equation , we get

in standard equation, coordinates of focus=(0,m)

thus for given equation coordinates of focus=(0,1.5)

step-by-step explanation: