Mathematics, 11.10.2020 08:01 Vanesssajohn2962

The equation (k + 3) x^2+ 6x + k = 5, where k is a constant,
has two distinct real solutions for x.
Show that k satisfies
k^2– 2k – 24 < 0

Answers: 3

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The equation (k + 3) x^2+ 6x + k = 5, where k is a constant,
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The equation (k + 3) x^2+ 6x + k = 5, where k is a constant, has two distinct real solutions for x. Show that k satisfies k^2– 2k – 24 < 0

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Another question on Mathematics

The equation (k + 3) x^2+ 6x + k = 5, where k is a constant,
has two distinct real solutions for x.
Show that k satisfies
k^2– 2k – 24 < 0