AP CAL AB HELP. A ladder 10 feet long rests against a vertical wall. Let θ be the angle between the top of the ladder and the wall, and let x be the distance from the bottom of the ladder to the wall. If the bottom of the ladder slides away from the wall, how fast does x change with respect to θ when θ=π/3 ?

Step-by-step explanation:

Please refer to the diagram below.

We can use the sine function. Recall that the sine function is the ratio between the opposite side and the hypotenuse. Hence:

We want to find how fast x changes with respect to θ. So, we want to find dx/dθ. Therefore, let's take the derivative of both sides with respect to θ:

Differentiate. Since it's with respect to θ, we can differentiate the left-hand side like normal. On the right, we will implicitly differentiate. This yields:

Multiply both sides by 10. So, dx/dθ is:

We want to find dx/dθ when θ is π/3. Thus, substitute π/3 for θ:

Evaluate:

So, x is changing with respect to θ at a rate of 5 feet per radian.

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35