There are 3 consecutive integers that have a sum of 36. What are the integers?

Step-by-step explanation:

The consecutive integers are increasing by 1

k ← the smallest integer

k+1 ← the middle integer

k+1+1 = k+2   ← the largest integer

k + k+1 + k+2 = 36

   3k + 3 = 36

     ÷3         ÷3

    k + 1  =  12

        -1       -1  

        k  =  11

k+1 = 11 + 1 = 12

k+2 = 11 + 2 = 13

the answer is 5/3x+7/5y+7

answer: true

step-by-step explanation: