PLEASE HELP I BEG 70 POINTS Part A: Explain how to sketch the graph of a curve that opens downwards and has only one x-intercept at (2.5,0).

Part B: Explain how to sketch the graph of a curve that opens upwards where the minimum value of the graph is (0,1).

Part C: Explain how to sketch the graph of a curve with the following characteristics.
• The graph opens downward.
• The y-intercept is (0,6).
The z-intercepts are (-1,0) and (3, 0).
• The maximum value of the function is located at the point (1,8).

Part A:

If a quadratic has only one x-intercept, then that is where the vertex lies. being that the vertex is the highest or lowest point in the quadratic. To sketch, it will open downwards with a single x-cept

Part B:

The graph will be above the x-axis. And having the vertex being at (0,1) as it says its the minimum value. All the minimum means is that its the lowest value of this given parabola.

Part C:

Plot the points of the y-intercept and z-intercepts. Then plot the maximum value is. Connect the dots.

maybe i can

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation: