Keith Hernandez has asked Jerry and Kramer to help him move into a new apartment on Sunday morning. He has asked them both in case one of them does not show up. From past experience, Keith knows that there is a 41% chance that Jerry will not show up and a 31% chance that Kramer will not show up. Even though Jerry and Kramer know each other, their decisions can be assumed to be independent. a. What is the probability that both Jerry and Kramer will show up? (Round your answer to 2 decimal places.)
Probability
b. What is the probability that at least one of them will show up? (Round your answer to 2 decimal places.)
Probability
c. What is the probability that neither Jerry nor Kramer will show up? (Round your answer to 2 decimal places.)
Probability

a. 0.41

b. 0.87

c. 0.13

Step-by-step explanation:

From the above question:

We are told that:

Probability that Jerry will not show up = 41% = 0.41

Probability that Jerry will show up =

100 - 41 = 59 = 0.59

Probability that Kramer will not show up = 31% = 0.31

Probability that Kramer will show up

= 100 - 31 = 69% = 0.69

Even though Jerry and Kramer know each other, their decisions can be assumed to be independent.

a. What is the probability that both Jerry and Kramer will show up? (Round your answer to 2 decimal places.)

= P(A) × P(B)

= Probability the Jerry will show up × Probability that Kramer will show up

= 0.69 × 0.59

= 0.4071

≈ 2 decimal places = 0.41

b. What is the probability that at least one of them will show up? (Round your answer to 2 decimal places.)

Probability = 1 - the probability that both Jerry and Kramer will not show up

= 1 - (0.41 × 0.31)

= 1 - 0.1271

= 0.8729

Approximately to 2 decimal places = 0.87

c. What is the probability that neither Jerry nor Kramer will show up? (Round your answer to 2 decimal places.)

Probability = Probability the Jerry will not show up × Probability that Kramer will not show up

= 0.41 × 0.31

= 0.1271

To 2 decimal places = 0.13

add an !

step-by-step explanation: