California has 143deaths from heart disease and 137deaths from cancer per100,000 residents. Which rate is more extreme compared to other states? A. Perform any needed computations here: b. Is California's rate for heart disease or for cancer more extreme compared to the other states? Explain:

California's rate for heart disease is more extreme than Cancer

Step-by-step explanation:

Given

Represent Cancer with C and Heart Disease with H

H = 143

C = 137

Population = per 100,000

First we need to determine the probability of both.

For H

P(H) = H/100000

P(H) = 143/100000

P(H) = 0.00143

For C

P(C) = C/100000

P(C) = 137/100000

P(C) = 0.00137

By comparison,

0.00143 > 0.00137

So, California's rate for heart disease is more extreme than Cancer.

Reason: P(H) > P(C)

1) c 2143.6 cm

2) c 113.0 m

3) a 33.5 ft

4)   d 2 cm

5) c 20 mm

6) 180 in

7) d 120 ft

3

step-by-step explanation:

in standard form:

a= dictionaries

b= maps

you have to buy 3 dictionaries, so put a 3 next to the a (dictionaries) so that you can multiply them by each other.

a3+b= 60 (the amount of money you have)

we already know the cost of a=15 so replace a with $15

($15 x 3)+b=60

multiply 15 and 3 to get $45 and replace it with $45

45+b=60

and then replace b with 15 to get the total:

45+15=60

that means you have $15 left after buying 3 dictionaries.

15 divided by the cost of a map ($5) equals 3.

so you can buy 3 maps.

sorry if it was confusing!