Let x = the length of the shorter piece of rope. x + (1/2)x = 24 (3/2)x = 24 (2/3)(3/2)x = (2/3)(24) x = 16 The lengths of rope are 16 feet and 8 feet. A student solves the problem to the left as shown. Which statements describe the solution? Check all of the boxes that apply.

Step-by-step explanation:

Given the question

A rope is 24 feet long. It is cut into two pieces such that one piece is half the length of the other. Find the lengths of the two pieces of rope.

Options

The stated solution is correct (lengths of 16 feet and 8 feet).

Based on the way the variable is defined, the equation should be x + 2x = 24.

The equation is written correctly, but there is an error in solving the equation.

The way the variable is defined, and because x=16, the longer piece of rope would be 32 feet, which is not possible.

2

Let the length of one piece be x (shorter piece) and the other be y.

If the rope is cut into two pieces and 24ft long, then;

x+y = 24 1

If one piece is half the length of the other, then x = y/2 2

substitute equation 2 into 1

y/2 + y = 24

take the LCM

y+2y/2 = 24

3y/2 = 24

cross multiply

3y = 48

Divide both sides by 3;

3y/3 = 48/3

y = 16 feet

Since x = y/2

x = 16/2

x = 8 feet

Based on the calculation above, I can conclude that;

- The student stated solution is correct (lengths of 16 feet and 8 feet)

- The way the variable is defined, and because x=16, the longer piece of rope would be 32 feet, which is not possible.

- Based on the way the variable is defined, the equation should be x + 2x = 24.

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can someone answer this question plz

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