A parking lot is 20 feet long. One tortoise starts at the edge of the parking lot and moves at a rate of 6 feet per minute. Another tortoise starts 4 feet from the edge of the parking lot and moves 2 feet per minute. Write an equation to represent when they will be in the same spot.

Kindly check explanation

Step-by-step explanation:

Length of parking lot = 20 feets

Speed of tortoise which starts at the edge = 6 feets per minute

Speed of tortoise which starts 4 feets from the edge = 2 feets per minute

Equation to represent when they will be in the same spot.

Distance = speed * time

Distance of Tortoise at edge = 6ft/min * t = 6t - - (1)

Distance of the other tortoise = (4 + 2t) - - - (2)

Equating both (1) and (2)

6t = 4 + 2t

6t - 2t = 4

4t = 4

t = 4/4

t = 1

Hence, they'll be at the same spot after 1 minute.

answer by yourhope:

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(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240