The sum of three consecutive integers is 71 less than the least of the integers. Find the integers.

-37, -36, -35

Step-by-step explanation:

x+x+1+x+2=x-71

3x+3=x-71

2x=-74

x=-37

So x=-37, x+1=-36, x+2=-35

Add these three numbers and you get -108 which is 71 less than -37

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

d

step-by-step explanation: