Select all figures with 180 degree rotational symmetry. a isosceles right triangle
b rectangle
C Square
d regular pentagon
e regular Hexagon

b, c and e.

Step-by-step explanation:

180° degree symmetry will mean that if we do a rotation of 180°, the figure will look exactly the same.

Now, let's suppose we have a figure with an odd number of sides.

We can draw that figure such that we have a side pointing down, and a vertex pointing up.

Now when we do a 180° rotation, the side will be pointing up and the vertex will be pointing down.

Then if the figure has an odd number of sides, it does not have a 180° rotational symmetry.

Now if the figure has an even number of sides, then we can do the same as above, but now we can put two parallel sides, one facing down and the other facing up, and when we do the rotation, we will end with the same image.

Then the correct options are the ones with an even number of sides:

b, c and e.

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841