If point (a, b) lies on the graph y=f(x), the graph of f^-1 (x) must contain point:

By the definition of inverse function,the point (a,b) lies on the graph So, (b,a) must be lies on the graph of .

Given:

Point (a,b) lies on the graph y= f(x).

Find:

The graph of   must contain that point.

As per the definition of inverse function, if two one-to-one functions f(x) and g(x). If (f∘g)(x)=x and (g∘f)(x)=x. Then, we say that f(x) and g(x) are inverses of each other.

Then, its inverse is defined as

Therefore, we have to interchange x and y-coordinate of the points which lies on the function f to get f⁻¹.

Thus, the point (a,b) lies on the graph So, (b,a) must be lies on the graph of .

For more details, prefer this link :

link

Given:

Point (a,b) lies on the graph .

To find:

The point which is must be lies on the graph of .

Solution:

According to the definition of an inverse function, if a function is defined as

then, its inverse is defined as

It means, we have to interchange x and y-coordinate of the points which lies on the function f to get f⁻¹.

We have a point (a,b) lies on the graph . So, (b,a) must be lies on the graph of .

Therefore, the correct option is (1).

good job you smart son of a gun you are smarter that einstein. 7

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm