Can you help me please (x-2)(x-3)=0

Explanation:

Use the zero product property. This is the idea where if A*B = 0, then either A = 0 or B = 0.

This works because 0 times any number is always 0.

In this case A = x-2 and B = x-3

So,

(x-2)(x-3) = 0

x-2 = 0 or x-3 = 0

x = 2 or x = 3

If we plugged x = 2 back into the original equation, we get

(x-2)(x-3) = 0

(2-2)(2-3) = 0

(0)(-1) = 0

0 = 0

Which confirms x = 2

Let's do the same for x = 3

(x-2)(x-3) = 0

(3-2)(3-3) = 0

(1)(0) = 0

0 = 0

So x = 3 is confirmed as well.

1. 22

2. 1

3. 7

4. 18

step-by-step explanation

e2020 got it right

step-by-step explanation:

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