given cos θ= √35/6 and angle θ is in Quadrant I, what is the exact value of sin θ in simplest form? Simplify all radicals if needed.

Here, I've attached a picture of the triangle that accompanies this explanation.

cot = = =

Now view the triangle.

PS. Angle theta will have a coordinate of (-, +) because it is in quadrant II.

sin of the angle would be opposite/hypotenuse, so sin =

cos of the angle would be adjacent/hypotenuse, so cos =

tan of the angle would be opposite/adjacent, so tan =

third option: 6x+8

step-by-step explanation:

we can see that the given question is a sum of series and the values of n vary from 0 to 3

the first term will be:

when n=0, [(0)*x+2] => (0+2) => 2

when n=1, [(1)*x+2] => (x+2) => x+2

when n=2, [(2)*x+2] => 2x+2

when n=4, [(3)*x+2] => 3x+2

so adding up all the terms will give us:

=2+x+2+2x+2+3x+2

=x+2x+3x+2+2+2+2

=6x+8

so,

third option is the correct answer ..

answer: r there any options?

step-by-step explanation: