Write an equation in slope-intercept form for the line that passes through (6, 6) and is perpendicular to -x+3y= -6

y= -3x+24

Step-by-step explanation:

First find the slope of the line

-x + 3y = -6

Add x to each side

3y = x-6

Divide by 3

3y/3 = 1/3 x -6/3

y = 1/3x -2

The slope is 1/3 since it is in the form y = mx+b where m is the slope

Perpendicular lines have slopes that multiply to -1

1/3 * m = -1

m = -1 * 3/1

m = -3

The slope of the perpendicular line is -3

Slope intercept form is

y = mx+b where m is the slope and b is the y interceot

y = -3x+b

We have a point ( 6,6)

6 = -3(6) +b

6 = -18+b

Add 18 to each side

6+18 = -18+b+18

24 = b

y= -3x+24

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).