The ages of three siblings combined is 27. The oldest is twice the age of the youngest. The middle child s three years older than the youngest. Write and solve an equation to find the ages of each sibling.

The ages of the children are 6, 9 and 12.

Explanation:

Let x= the age of the youngest child.

If the oldest child is twice the age of the youngest, the age of the oldest child is twice x or 2x.

If the middle child is 3 years older than the youngest, the age of the middle child is x+3.

If the sum of their ages is 27, then

x+2x+x+3=27aaa(Combine like terms)

4x+3=27aaa

aa−3a−3aaa(Subtract 3 from both sides)

4x=24

4x4=24aaa(Divide both sides by 4)

6, 9 & 12

Step-by-step explanation:

let x represent the age of the youngest kid

if the oldest kid is twice the age of the youngest, then it would be 2x

if the middle kid is 3 years older than the youngest, let this be x+3

if their ages in total is 27, then the equation is

x+2x+x+3=27

combine like terms first

4x+3=27

subtract 3 from both sides

4x=24

divide both sides by 4

you get 6. The youngest kid is 6.

For the oldest kid, the equation is 2x=2 times 6=12

the age of the middle child, equation is (x+3)=6+3=9

Hoped this helped!

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

the answer is  

a.

4,624π mm2

step-by-step explanation: