Which is the solution to the following system x+2y+z=9
X-y+3z=13
2z=10

Step-by-step explanation:

I'm not sure but,here you go

2z = 10

z = 10 ÷ 2 = 5

x + 2y + z = 9

x + y + 3z = 13

x + 2y + 5 = 9

x + y + 3(5) = 13

x + 2y = 9 - 5

x + y = 13 - 15

x + 2y = 4

x + y = -2 (×-1)

x + 2y = 4

-x - y = 2

y = 6

x = -2y - z + 9 = -2(6) - 5 + 9 = -12 - 5 + 9 = -8

If you wanna check,

x + y +3z = 13

(-8) + 6 + 3(5) = 13

x = -8 , y = 6 , z = 5

I'm not very sure but here you go,I might be wrong^^

q1 a person or thing situated away or detached from the main body or system. a cluster is a a mash of many things.

q2 do

step-by-step explanation:

your answer is the frist one

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