A hockey team has four left wingers, three right wingers, four centres, three left defence, four right defence and two goalies. To create a starting lineup, a coach needs one player in each position. In how many ways could the starting lineup be chosen?

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8