Problem number 26 of the Rhind Papyrus says: Find a quantity such that when it is added to StartFraction 1 Over 4 EndFraction of itself the result is a 15. The modern day equation that models this problem is x plus StartFraction 1 over 4 EndFraction x equals 15.. What is the solution to the equation? x = 10 x = 12 x = 15 x = 30

The quantity is 12

Step-by-step explanation:

Here, we want to find the solution to the equation.

Let the quantity we are looking for be x;

According to the question;

The quantity plus a quarter of the quantity = 15

x + 1/4(x) = 15

x + x/4 = 15

Multiply through by 4

4x + (x/4)*4 = 15 * 4

4x + x = 60

5x = 60

x = 60/5

x = 12

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

yes

step-by-step explanation: