Mathematics, 13.10.2020 08:01 beccadoyle0809
Identify whether each equation has one solution, infinitely many solutions, or no solution.
2(x - 5) = 2(x - 5)
One Solution
Infinitely Many Solutions
No Solution
5(x + 4) = 5(x-6)
5(x + 4) = 3(x-6)
4(x - 2) = 4(x + 2)
x + 2(x - 5) = 3(x - 2) - 4
Answers: 2
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(01.04 lc)multiply 1 over 6 multiplied by negative 1 over 2. negative 1 over 3 negative 1 over 12 1 over 12 1 over 3
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Identify whether each equation has one solution, infinitely many solutions, or no solution.
2(x - 5...
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