Can someone please help. I'm offering a lot of points because this answer needs an explanation. Statement proof style would be helpful, but it's not totally needed

See below

Step-by-step explanation:

As CD⊥AB, ∠BDC = ∠ADC = 90°

∠BDC ≅ ∠ADC

and

We can substitute ∠ADC with ∠BDC and ∠DAC with ∠DBC

Then we get same equation for ∠BCD and ∠ACD

Therefore ∠BCD = ∠ACD = 1/2∠ACB

It proves that CD bisects ∠ACB

b. ol

step-by-step explanation:

i got the answer right on edg.

congruent: (geometry) (of figures) identical in form; coinciding exactly when superimposed.